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AP 3302 Pt. 3 Section 1 CHAPTER 5 Basic outline of CW radar where: Fd = Doppler shift in c/s If the transmitted frequency is 1,860 Mc/s and the velocity of a target directly approaching the aerial is 360 m.p.h. then: Doppler shift Fd = (2 x 360)/(186,000 x 60 x 60) x 1,860 x 106 = 2 Kc/s
In practice it is the velocity of a target we wish to find, so we work the other way round from the measured value for the Doppler shift and the other known factors. Knowing the relation-ship it is simple to convert any difference in frequency between the received signal and the trans-mitted signal into the relative velocity of the target. So far we have assumed that the target is moving in a direct line either towards or away from the radar aerial. If the target is not moving along such a path, the difference in frequency which Doppler effect causes is less. From Fig 7 we can see that the important factor is the radial velocity, i.e. that component of the target's speed which is in a direct line with the aerial. When the target is not moving along a radial line the radial velocity is less than the actual velocity. In fact if the target is moving at right angles across a radial line its radial velocity is zero. It is only the radial velocity which can be measured by the Doppler effect.
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Constructed by Dick Barrett |
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©Copyright 2000 - 2002 Dick Barrett |
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The right of Dick Barrett to be identified as author of this work has been asserted by him in accordance with the Copyright, Designs and Patents Act 1988. |